Introduction[]
In Sekirei chapter 155, Mutsu destroys the ground to escape from Akitsu's Norito. This attack caused a earthquake that was felt by Minato and his Sekirei.
Right when Minato feels the rumble, the barrier around the island falls. Later on Mutsu admits that his attack caused the barrier to disappear, this shows that the rumble they felt came from him striking the ground.
Note: They're on a island, and there's a ship underground that created a barrier.
I'll be calculating Mutsu's Attack Potency
Calculation[]
Lucky for us, Kamikura Island length is something the manga tells us.
Kamikura Island Length = 2 km
Now we need to find the distance between Minato and epicenter. Once again, the manga gives us a nice picture of where everyone was at before the Earthquake happened.
Minato is at point 3 while Mutsu is at point 1 when he causes the quake.
Kamikura Island has a length of 2 km or 204 px.
This means each px is 0.0098039215686275 km, or 9.8039215686274996386 m
The distance between point 3 and 1 is 80 px, or 784.31 m, or 0.78431 km
Now I should be able to calc the energy of the earthquake. The earthquake visibly caused Minato, Homura, and Kuu to shake, made Himiko fall and drop her weapon, and destroyed the island's barrier. So the magnitude of this should be IV to V on the Mercalli Scale, since this type of earthquakes makes rattling noises and are slightly felt outside. The average between these two magnitudes is 4.5
Magnitude at the epicenter = 4.5 + 0.0238 x 0.78431 = 4.518666578
Energy = 10^[1.5*(4.518666578)+4.8] = 378442468821 Joules
Final Tally[]
Mutsu's Attack Potency = 90.44 Tons of tnt (City Block level+)