Urie Combat Speed Calc[]
In the most recent episode of Tokyo Ghoul Re, Urie slices apart two ghouls by completing 4 slashes seemingly simultaneously within less than a second. I'm going to try and calc this to see if it gives anything nice.
At this stage in the series, the tokyo ghoul wiki states that Urie's is 173.5 cm tall.
I'll be using this nice full body shot of Urie walking away as my measurement because it was the first full body shot I came across. I might try this again if I find a better shot, but this works for now.
Let's have my first go at working with pixels then.
The left photo shows that Urie's 173.5 height has a pixel height of 271 px (highlighted at the bottom of the photo). That means that each pixel is equal to 0.640221402 cm.
I'll round that to 0.64cm per pixel
Arm Triangle Vertical Side = 97 px
Arm Triangle Horizontal Side = 12 px
Length of arm = c
97^2 + 12^2 = c^2
c^2 = 9553
c = 97.7394495585 px
Round that to 97.7px I guess (or do pixels get rounded to whole numbers?)
97.7 x 0.64 = 62.528cm
According to this, since these are slashes, the distance moved is assumed to be 1/3rd the circumference of a circle. The radius of this "circle" *(the motion of his arm) would be 62.528 centimeters.
I'll use the same tool that calc did
https://www.calculatorsoup.com/calculators/geometry-plane/circle.php
From that, we get that if the radius is 62.528 centimetres, the circumference is 392.87501088733 centimetres, and since he slashed, it is 1/3rd of this. So each slash covered 130.958336962 centimetres.
Urie did 4 slashes (first picture), so he covers a total of 523.833348cm, or 5.23833348 metres
Now for the timeframe.
It's a bit hard to tell seeing as the video player I'm using counts the timer down from the end instead up from the start, but you can see that both images show the same timestamp (bottom right corner of the images). So he does it in less than a second, so if I just use a single second as the time frame that's...
5 m/s.
> Normal human
Bloody hell that's underwhelming.
Even using 0.5 seconds only gets it up to 10m/s, which is Peak Human
I want to call bullshit on that, seeing as I as a normal human certainly couldn't wave my arms 5 metres in a second or less, but... what the hell.
Guess this feat is no use then. Sigh.
Fodder ghoul punches a wall (calc incomplete, on hold)[]
During the original series, a ghoul punches a wall hard enough violently fragment it. Having seen the size of some fragments in other calcs that are considered to be violently fragmented, I think it is fair to use the high end of violent fragmentation, that is 20 joules/ cubic centimetre.
Shachi busts a Bridge[]
In Chapter 65 of Tokyo Ghoul re:, Shachi busts a bridge by punching it . From the photos, it looks like fragmentation to violent fragmentation, so I'll be using Fragmentation as the low end, and the two ends of Violent Fragmentation (for concrete) as the medium and high ends respectively.
From this panel, we see the destruction reaches up to where Arima is walking.
In the first image I showed, we can see where that it is, and in the third image we can see that he did a bit of damage to the floor he was already on as well.
Arima is listed as being 180 cm tall in the Tokyo Ghoul fact sheets. I'll use the first image to get the heights.
15^2 x 97^2 = 9634
Square root of that is 98.15
180/98.15 = 1.83392766174 = 1.834cm/px
Size of the Bridge
I'm just going to use a rectangular prism for the bridge. The damage extends a bit beyond it, but I'm lazy.
The length and width are easy enough. Using the pixel scaling I just got 148.584819 cm for the width, and 500.662252 cm for the length. Depth is a bit more difficult, due to the angle, but I'm just going to use the pixels anyway. Pretty sure it still counts as a low-ball, but oh well. Not sure how accurate this is due to the angles, but it gets a depth of 44.087621 cm for the bridge.
Length: 500.662252 cm
Width: 148.584819 cm
Height: 44.087621 cm
Therefore Volume of the bridge = 3279713.84 cc
Destruction values
Pretty sure this bridge is made of concrete, but then again it is in Cochlea, so it might be made of steel. I'll use concrete until something says otherwise.
Low End
= 3279713.84 cc X 6 joules
= 19678283 joules
= 1.9678283 x 10^7 joules
= Wall Level
Medium End
= 3279713.84 cc X 17 joules
= 55755135.3 joules
= 5.5755135 x 10^7 joules
= Small Building Level
High End
= 3279713.84 cc X 20 joules
= 65594276.8 joules
= 6.5594276 x 10^7 joules
= Small Building Level
Huh. Quite impressive for a punch without using a Kagune . I guess I'll let other people decide which, but personally I'd probably go for the low end, as it fits better with Wall level ghouls in base, even if Shachi has trained himself up ridiculously.
Saiko Megaton Punch[]
Saiko punches Urie into the street hard enough to cause a large crater.
Going to be difficult to work out the exact size of the crater (though I can do a rough estimate).
Ok, the way I'm going to do this is compare the size of her own body in the top frame to the width along the knuckles of the big fist she's made in the same frame to determine how big the fist is, then apply that size to the lower frame's fist and pixels to work out the size of the crater she's created.
So, the width of the fist along the knuckles is found with the Pythagorean Theorem along that red triangle. The triangle is 46px by 73px on its base and height respectively, so plugging it into Pythagorean Theorem gives us a hypotenuse length (and fist width) of 86.28 px
Putting that aside for now, Saiko is listed as being 143cm in height. It's a bit of an odd angle, but I'll try to work out how many pixels that is.
The yellow triangle shows the length of her lower leg from the knee to the base of the foot. The base of the triangle is 33px, while the height is 5px. That gives us a hypotenuse (lower leg length) of 33.38 px
The bend at her knee is the only significant curve in her posture here, so I'll just use a straight line from her knee to the top of her head from there. The blue triangle is 14px by 113px, giving a hypotenuse of 113.86
113.86 + 33.38 = 147.24px
143cm/147.24px = 0.971203477 cm/px
Plug that back into the width of the fist, and we find that the fist is:
0.971203477 x 86.28 = 83.795436 cm
Great. Now we compare it to the bottom panel.
The green triangle shows the width of the fist. There is a little bit outside the green length, but based on the way it angles away from the marked area, and the indent mark in the middle, I believe that is where the fingers have curled to make a fist, so it does not count for the width of the fist from knuckle to knuckle.
The green triangle is 31px x 11px along its base and height which gives a hypotenuse of 32.89px.
Divide that by the established width of the fist, and we find that each pixel in this lower frame must be:
83.795436cm/32.89px = 2.54774813cm/px.
Next, we multiple this number by the pixel width of the crater. As she created the crater by hitting the ground from above it, I will assume the crater is a circle, and use this width to find the the radius and thus the area.
The horizontal red line shows the width of the crater from where the chunks of rock are being thrown up to be 757px. Multiply this by the cm/px number, and we get the crater to be:
757px x 2.54774813cm/px = 1928.64533cm.
Half that would be the radius, so we have a radius of 964.322665cm
Feed that into the area of a circle formula, and we get an area of 2.92×10^6 square cm (292 square metres).
That is more than I thought this would be.
There are two ways to work out the depth of the crater. The easiest, though also the most low-balling, would be to just compare the depth of the cracked slabs of concrete she's throwing up.
I'm just going to do that.
I'll use the one with the yellow triangle on it because it seems to be good median size, and because it has a similar angle to the "camera" to the fist.
Base = 16px
Height = 6px
Hypotenuse = 17.09px
17.09px x 2.54774813cm/px = 43.5410155cm
All the other slabs of concrete she's throwing up are of a similar depth, so it's fair to assume that's how deep (at minimum) the crater is.
So the volume of the crater is 2.92×10^6cm x 43.5410155cm
= 127,139,765 cc
Those slabs are pretty big, so I'll just use fragmentation of concrete rather than any larger destruction value.
127,139,765 cc x 6 j/cc
= 762838590 joules
= 7.62838590 x 10^8 joules
= Small Building level+