This a revision on this calculation here. The numbers I use is based on this accepted calculation .
@WeeklyBattles seems to think it's invalid, so I will re-do it.
This calculation has accepted the volume of the teeth as 35.64 cubic meters, so that is what I will be using to determine the density. Rather than treating the material as a litteral diamond, I will start by using regular teeth:
According to wikipedia, Calcium Phosphate has a density of 3.14 g/cm3
I have decided to re-do the calculation with that in mind.Unforunately the calculator could not let me use said material so I chose something with a comparable density, Calcium Difluride, which has a density of 3.18 g/cm³. In practice, this would only amount to a difference of a few pounds.
Using the accepted volume (from an accepted calc) of the teeth as 35.64 cubic meters and we get 113.34 tonnes, or Class K lifting strength.
So even assuming they are regular teeth, it would still be a Class K lifting feat.
However, @WeeklyBattles has suggested that the stand could be made out of a the material it is possessing, which makes sense, so I redid it for that scenario too:
The sea-bed (which is what the stand was possessing) is largely made out of mafic rocks or sima, which is heavily rich in and primarily iron (which makes sense, considering the stand possesses metals). So I will use the calculation assuming it is iron, then divide the calculation by half to account for any foreign materials that may be within it.
The density of iron is 7.874 g/cm. Assuming it is still 35.64 cubic meters, we would get 280.63 tonnes. Dividing that by two leaves us with 140 tonnes, or still Class K lifting strength.