Introductions[]
Ann entry to the NF Project.
Those calculatios aren't mine, but Deer Lord's. Full credits to him.
The Calculations[]
1[]
Noticed an impressive feat for base Mushra while I was doing my respect thread, seems like an upgrade so lets calc it
Feat here: http://[Blocked Domain]/shinzo-episode-17 at 13:20
Spoiler: Show
Caris went through the wall, so the hole has to be at least as tall and wide as he is.
http://i.imgur.com/Ps5Yv75.jpg
Mushra's height in base is 1.3m
184 px = 1.3m Caris' height= 822 px = 5.828 m Caris' width = 218 px = 1.545 m
Now for the depth of the hole, I'll use the same dimensions as the debris from the attack, since I can't get a clear view of the hole due to dust.
http://i.imgur.com/u9OJpV8.jpg
Yakumo is a 14 yo japanese girl, so her height is about 1.56m
534 px = 1.56 m Hole's depth = 44 px = 0.128 m
Volume destroyed = 5.828*1.545*0.128= 1.157 m^3, or 1157401.51 cc
The wall seems mostly concrete, but it is plated with steel on the inner side, so I'll use 90% of the volume as concrete and 10% as steel.
V(concrete)= 1041661.36 cc V(steel)= 115740.15 cc
Fragmentation of concrete = 6 j/cc Fragmentation of steel = 208 j/cc
Energy= (1041661.36*6)+(115740.15*208)= 30323919.36 J, or 0.0072 tons of TNT
Small-building level base eterrans.
2[]
I'm bored, so here's another calc. pumped full of nostalgia this time.
[YOUTUBE]NiSu53cXKrI[/YOUTUBE] jump to 25:16, also disregard the silly vid title
So here we find out the reason they didn't get to shinzo is because General Mushrambo blew it up back when he was still a dick.
Haven't seen anyone try to calc this, so I'll give it a go.
The calc: Spoiler: Show
The explosion itself seems like textbook nuke. For this reason I'll be using nuke calculator, but first I'll have to find the fireball radius.
When we get to see a view of the city from above, just as Mushrambo nukes it we see it has a convenient circular outline. The actual fireball covers that circle and then some, so I'll try to find its diameter.
http://i.imgur.com/r1oT7DV.jpg
- re-scaled this thing a couple of times, eventually figured out the best angle is the same as the shadow in the back= -23 degrees.
The first scaling I do is from a random person to get the landing pad width.
Person's height= 49 px Average human height= 1.72m Therefore, 1px=1.72/49= 0.0351m
Lane width= 791px = 791*0.0351=27.7657m
Now for the overlook of the city:
http://i.imgur.com/5O7hNHx.jpg
Lane width= 27.7657m= 30 px 1px=28.874/30= 0.9255238m
Fireball Diameter= 1088px= 1006.9699m so, Fireball radius= 503.48495m
Plugging that to nuke calculator gives a yield of 1.47 Megatons
Here's a second method suggested by TotalyNotaCat
I'll be using rock melting for the crater the blast left (although it seems most of it evaporated)
http://i.imgur.com/ELjNmvL.jpg
Crater length= 1164 px = 1006.9699m 1 px = 0.8651m Crater width= 2*313 px= 626 px = 541.5491m Crater depth= 1006.9699/4= 251.742475m
I'm calculating this as half an ellipsoid using this calculator
And get a crater volume of: 71880228.221 m^3 or 71880228220809.45 cc
Melting of rock = 4300 j/cc energy= 71880228220809.45*4300= 309084981349480635 J or 73.873 Megatons
3[]
So I'm going over this show looking for quantifiable feats, might make a respect thread once I'm done
Here are a bunch of feats from the first 11 episodes:
1. Kutal pushes subway cars Spoiler: Show
The gang requires some transportation in ruined NYC. They hop on an old subway car and kutal gets it going.
http://[Blocked Domain]/shinzo-episode-2 8:30
I'm going to assume said car module is this one: https://en.wikipedia.org/wiki/R143_(New_York_City_Subway_car) Since it fits the time the show aired.
Kutal is pushing two cars here (as seen later), with a combined weight of 75,000 kg.
I'm assuming that to get the cars going by themselves he was pushing them in a similar acceleration as irl, hench 4 kmph/s, or 1.111 m/s^2
Timeframe between that beginning of movement untill the car gets going on its own is 6 seconds.
So, dv= a*dt= 1.111*6=6.666 m/s Thats the change in speed, looking for distance I'll assume: median velocity*time= 20 m (rounded from 19.998)
F=m*a=75000*1.111= 83325 N W=F*d=83325*20= 1666500 J
Wall-level+, but it's only for base-form anyway.
2. Mushra is a dick to mountains
Spoiler: Show
During a battle with some Spider Enterrans, Mushra decides that "fuck this shit" and nose dives into their hideout (inside a mountain), blowing up most of it.
http://[Blocked Domain]/shinzo-episode-3 17:10
You can't see the entire thing in this shot, but in other shots it appears that the part displayed in this screencap is roughly 2/3 of the whole spire.
scaling: Double story building= 12 px = 6m Front hill= 44 px = 22m
assuming all the hills are roughly the same size Back hill= 30 px= 22m 2/3ds of the Spire= 283 px = 207.533m Full Spire height= 311.3m Spire width at base= 153 px = 112.2m
Shaping it like a cone: V=1.03e6 m^3
The spire is home to the spider-enterrans so I'll assume it's about 50% hollow. Moreover, as seen at the end of the episode, Mushra did not destroy the whole thing, about 1/3 remained standing.
the volume I'll work with is therefore: V= 343333.33 m^3, or 343333333333.33 cc
Fragmentation of rock= 8 j/cc Energy= 343333333333.33*8= 2746666666666.66 J, or 656.47 tons of TNT Multi City-Block+ level
3. Mushra, Sago & Kutal VS Gyasa
Two speed feats here
http://[Blocked Domain]/shinzo-episode-9 3:25 and 10:13
Starting with Mushra's feat
2*atan(105/(768/tan(70/2)))= 10.936693172194 degrees
2*atan(169/(768/tan(70/2)))= 17.518738966294 degrees
Mushra's height= 1.85m Gyasa's head= 0.223m
Using angular calculator: Distance=9.6624-0.72364= 8.93876m
Mushra's red flare is visable in front of gyasa within 1 frame 1 frame= 0.04s
v= 8.93876/0.04= 223.469 m/s Faster than the eye can track.
Second feat is Kutal rapid punching Gyasa. Viewing the video frame by frame we can see Kutal throws 3 punches each frame. Meaning he's throwing the punches and retracting his arm three times between frames, so he moves the distance of his arm
Kutal's height= 2.15m Arm (fist shaped) lenght*= 0.419*height= 0.90085m Distance= 5.4051
v=5.4051/0.04= 135.1275 m/s a bit slower than Mushra.
4.Mushrambo VS Hyper Gyasa
Spoiler: Show
http://[Blocked Domain]/shinzo-episode-11 8:13
To calc this , I'll first have to get an understanding of how tall are the hills they are fighting around
Scaling from a previous ep:
Pretty much all the hills in the fight are a result of splitting this one. In my previous entry I have already found out that the average height of forest canopy here is at least 25m.
Tree height= 36 px = 25m Hill height= 263 px = 182.638m
Now for the speed feat:
Mushrambo and Hyper Gyasa are engaged in an aerial battle. Each light is them crossing swords. I picked the movement that seemed most in-line angle-wise and in the front.
We can see the top part of a hill in the front. I'll call it the top 1/4 for conservative measures.
Top part of the hill= 71 px = 182.638/4= 45.66m Distance crossed= 614 px = 394.858 m
Timeframe is 8 frames= 8*0.04= 0.32s
- from the point the light starts to fade untill the next one appears.
v=d/t= 394.858/0.32= 1233.932 m/s, or Mach 3.626
Finally some supersonic values.