This infamous feat. Original calc made by the user Regicide, can be found here. So, copy-pasting:
Alright, so..
Like I said, don't actually follow Dragon Ball Super myself, so correct me if I'm wrong on any of these points.
First off, figuring out the energy needed to shake Kaioshin Kai (assuming that's where this is happening), which Chaos already found the size of in X.
Diameter is 3919012.776 km.
Basically I figure the shaking of a planet can be treated as being like a planet-wide earthquake, and thus I can quantify this in the same way that GM got a value for X.
Conveniently, the parameters for the intensity of the earthquake remain the same here as in his calc, if not even higher in this case.
So I don't have to change anything in that regard.
I just need to account for the actual distance traveled by the "earthquake" in this case (i.e, it travels across half the circumference of the planet) and follow the steps that were already provided in the blog.
I'll leave the rest of the explanation to the original calc in question.
Circumference of a circle = PId
3.14*3919012.776 = 12305700.11664 km 12305700.11664/2 = 6152850.05832 km
Converted to miles, 6152850.05832 km is equal to 3823203.776 miles.
3823203.776/5.7 = 670737.5s
Which gets plugged into..
log(base10)50+3log(base10)[8*670737.5]-2.92 = 18.96
Which is the magnitude of the earthquake, which converts to 1.737801*10^33 joules.
Not done yet though. This was caused by a shockwave.
Basically, by comparing the cross-sectional area of the planet to the surface area of the omnidirectional shockwave, I can figure out how much energy was emitted on that fraction of the shockwave's edge and then account for the entire surface area.
Gonna be treating it like a sphere.
The DB universe is made up of four quadrants dividing the thing into four galaxies, correct? Hence the minimum radius for this shockwave and whatnot would be 100,000 light-years.
100,000 light-years is equal to 9.4605284*10^17 km.
Area of a sphere = 4PIr^2
4*3.14*(9.4605284*10^17)^2 = 1.124140*10^37 km^2
Area of a circle = PIr^2
Radius being that of the planet here.
3919012.776/2 = 1959506.388 km
3.14*1959506.388^2 = 12056548993684.21 km^2
And now just multiplying the earthquake energy by the ratio of the two areas.
(1.737801*10^33)*((1.124140*10^37)/12056548993684.21) = 1.62*10^57 joules
Divide that by two to get the individual energy since two people contributed to this.
Meaning the final value is 8.1*10^56 joules.
Which is galaxy level+.
Seeing as how the GBE of the Milky Way is just 1.0*10^54 joules.
Wouldn't be surprised if I'd f**ked up somewhere down the line, so someone check my math.
Correction[]
The user use 4 Galaxies as the size of the universe, something that was reconnected long ago (If someone can link me the panel where this is stated I would appreciate it), so going the replace the 100000 lightyears with the 4.4*10^23 km, so the new result would be:
1.62*10^57*[(4.4*10^23)/(9.46052*10^17)]^2 = 1.62^57*216*10^9 = 3.5042*10^68 J Result is divided by 2 since it were made by two people ==> 1.7521*10^68 J (Galaxy level+)
Now, I heard that the Earth is localized at the edge of the universe, something that could change the result, but I have no proof right now