Sorry about being a bother, but I would very much appreciate if you could consider if there are any members of this wiki that you think would be good additions to the calc group, and then send me a PM with the suggestions.

Since I've been pretty busy the last month, I been a little inactive here and only revised a few calcs of non-staff members, that at the time they were amateurs. Would wait a little more to suggest a promotion.

This page is designed to act as a reference page for experienced and new calcers alike, alongside giving easy examples and guides to new ones. Ant wishes for me to gain the calc group's approval on it, and I would love your input. Thanks for your time!

It's about this blog. Since we back then decided to not use it I never actually checked your results.

Since you recently mentioned it in that one thread I supposed I should do it. Especially since I know how to do it with a computer now, which makes that a lot less work ( ͡° ͜ʖ ͡°)

Long story short, solving P= 6784*W/R^3+93*sqr[W/R^3] to W I get what I believe is a different result.

I get W = R^3*((27136*P + 8649)^(1/2)/13568 - 93/13568)^2.

For 1000 random test value between 0 and 1000 I get correct results with this and transforming it backwards it indeed checks out.

W = R^3*((27136*P + 8649)^(1/2)/13568 - 93/13568)^2

Those are obviously not the same. Not sure if they are approximately the same and the equation became this complicated due to rounding errors in your equation or there is a bigger mistake. That said, it's at least somewhat off, I believe.

I'm grad to see you again, DT, as been a long time.

Yes there are two different results, but only the one that involve the sustraction is the correct; not sure about the theorical explication, but replacing the + result in the original equation gives you a bad result/inconsistence. Futhermore, the bigger the pressure, the difference between both results becomes negligible. I used the same equation to determinate near-total fatalities ratio (20 psi), and the result is pretty similar used by the Nukemap (can't link cuz using a phone).

Ok, I checked it and indeed one of the solution from your formula matches the actual results with an error of on average 0.023 (from 1000 tests) for values between 0 and 1000.

That explains why the solution to your equation is so complicated.

So, in this case, take this just as the helpful hint that W = R^3*((27136*P + 8649)^(1/2)/13568 - 93/13568)^2 is easier to calculate and has a way smaller error. (and it's way easier to varify that the result is correct xD)

Checking: replacing P by 20 psi give me a result of 80.3686*10^(-6)*R^3; yep, thats the equation for near-total fatalities, so it works. There other values for pressure in order to use as references, ex. 10 psi is able to destroy reinforced concrete but 50% of people is able to survive, 5 psi is for eardrum rupture, and 1 psi is for glass destruction.

What about the scaling tnt part, it can be useful?

It was added?... hmm... staff at the start seems to disagree and the attack doesn't fill the requeriments, not sure why should have been added. Oh well, I'm not the one with the ast word, if people want it in that way, then let them be.