# Explosion Yield Calculations

*11,372*pages on

this wiki

## Step 1: Find the Size of the Explosion

First, you have to find the exact page, or scene where an explosion is shown as a feat. Depending on the environment where the explosion occurred, you may have to scale the size of a smaller object that is shown in the map. Let's do an example...

### Example 1: An Explosion Occurs

An explosion of unknown size occurs in this picture, engulfing the object. Find the size of the explosion. The explosion is shown in the below scene.

- The first thing that notice is that you do not know the exact size of the object shown in the picture.
- However, you are allowed to find the size of the object by comparing it with an another object, such as the one shown beside the object.

## Step 2: Finding the Radius of the Explosion

From example 1, there is a scene that shows the object in relation to the object shown from the first picture. This is located below. We will use the height of the door as a reference in this case.

- Given that the door size of the door is 7 feet, or 2.13 metres tall, you can now find the size of the object.
- Log down the size of the object.
- After you have found the size of the object, you compare the size of the object to the diameter of the explosion shown in the first picture.
- Divide the diameter by two to get the radius of the explosion.

## Step 3: Finding the Yield of said Explosion

Here is a sample calculator that you can use in order to find the yield of an explosion, provided that you have found the exact diameter of it.

- Generally, you take the
**near-total fatalities**section from the list of calculated values/calculator above. - As for why it is used, the definition of near-total fatalities means states that: all large above-ground structures are destroyed within that radius, as well as causing 100% fatalities to anyone that is affected within the radius due to sheer pressure alone.
- When you get the result of said explosion,
**you multiply the value by 0.5**. This is because only 40 to 50 percent of the total energy of the explosion is actually from the blast. - Keep in mind that if the explosion is an actual nuclear explosion, you can disregard the point above.

If you are having a hard time using the nuclear calculator, this equation can be used to find the yield of said explosion.

- Air blast radius (near-total fatalities) Yield:
**Y**= ((x/0.28)^3)/1000

## Misc 1: Somebody Tanks an Explosion!

Let's say an explosion occurs in front of a character, and said character takes the explosion at close proximity. To find the actual amount of the energy from the explosion that he/she

- First, the energy radiating from explosion only makes contact with the front of the body, and not the back as well.
- Second, the surface area of the person making contact with the explosion must be calculated.
- Here is a calculator you can use to find the surface area of a person. Just make sure to multiply the final result by 0.5 (divide the final result by 2) at the end.

## Misc 2: The Inverse Square Law

- Applies when a energy is directed outwards from the center in a 3-Dimensional space.
- The intensity of said energy decreases proportionally as the energy is directed further away from the source.

As for how this relates to explosions?

- This means that further you are away from an explosion, the less damage you will take from it.
- Power of said explosion is distributed over a larger and larger surface area as the distance from the epicenter increases.
- The surface area of a sphere is
**A**= 4πr^2. This is relevant because when an explosion occurs, the energy of said explosion radiates outwards as a sphere. - The intensity of said explosion at a distance of r is
**I**= P/4πr^2, where I = Joules of energy. - P = Power/Yield of explosion, in Tons of TNT

Let's do an example.

### Example 1

If an explosion of 7 kilotons of TNT occurs, find the intensity of the explosion at 300 metres away from the epicentre.

- First, we set
**P**= 7000 Tons of TNT, as that is the yield of said explosion - Second, we set the radius, or
**r**= 30m - Third, we find the value of I, or the intensity of the explosion at a specific distance.
**I**= (7000 Tons of TNT) / 4π(30m^2)- This means at 30 metres away from the epicenter of the explosion, the shockwave is hitting with a force of
**I**= 0.619 Tons of TNT.