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Calculations Example

Calculating Destructive Capacity

In order to determine a character's Destructive Capacity, we must first look through the character's feats, and determine how much energy was exerted to preform such a feat. Sometimes the destructive capacity of the feat can be determined easily with no need of a calculation, but most of the times it isn't as simple. Here we will explain some of the methods we use in order to calculate feats.

Destruction/Creation of Planets and Planetoids

For feats that involve the Destruction or the creation of planets or planetoids, we use a term called Gravitational Binding Energy, more information about the subject on the GBE page.

Meteors and Kinetic Energy

In order to determine the energy of meteors, we generally use Kinetic energy, as it is the most reliable way to gauge the energy a meteor poses if we are given the required Details.

The equation used:

Ek=0.5*M*V^2

Terms:

Ek=Kinetic Energy

M=mass

V=velocity=speed

There are several speed values that we can use without the need for proof:

If the meteor in question was determined to have come from outer space (or outside of our atmosphere) we will use the value of minimum impact velocity, which is the minimum value of speed an object needs to enter the earths atmosphere, that value is 11,000 m/s.

If the meteor in question was shown to be Ablated, but didn't come from space, we will use Ablation speeds, which are the minimum speed an object needs to move in order for it to be ablated by its own friction with the atmosphere, the values range from 2000-4000 m/s.

A reasonable high end for meteors that come from outer space is 17,000 m/s, as it is the speed value of most of the meteors that have entered earths atmosphere.

If the meteor in question wasn't ablated and didn't come from outer space, we will use Potential-Gravitational Energy, as it does not require the use of speed. That is unless we can mathematically find a speed for the meteor.

Potential Gravitational Energy: Energy of falling Objects and Energy to lift Objects

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. If an object from a high position falls towards the ground the kinetic energy the object gets from falling is equal to the difference in its gravitational potential energy before and after the fall, provided no other forces such as air resistance act upon it. Vice versa the energy necessary to lift an object to a certain height is also equal to the change in gravitational potential energy of the object before and after being lifted.

However, lifting should generally not be used to calculate Attack Potency unless it is a fast, explosive form of lift (for example: snatch, clean-and-jerk, etc.). This is based on the biomechanics behind how human type characters attack. Unlike a punch, a kick, or most other types of attacks, a lift is a slow sustained motion which allows for many more muscles fibers to be recruited into the movement more easily, generating much more energy than a fast movement used in combat. Lifting movements also allow the body's tendons to help out by storing the energy, then releasing it in a sudden burst, acting like a spring. If we use real world ratios, when the world's heaviest deadlift is compared to the world's most powerful punch, the deadlift has nearly 5 times more energy, demonstrating the disparity between the two types of movements. Similarly, if telekinesis (or any other ability of a similar nature) is used, the lifting must be performed in a timeframe capable of being used as an attack.

In cases close to the ground

In cases where an object is lifted or falls relatively close to the surface of the earth the difference in gravitational potential energy can be calculated using the simple formula

Ep = M*g*h

where

  • M = mass of the object in kg
  • g = the gravitational acceleration. For earth this is about 9.81 m/s2
  • h = how high the object was lifted / how far down the object fell in meter
  • Ep = gravitational potential energy difference in joules.

In cases far away from the ground

In cases where an object is lifted very high or falls from very high up the upper formula can not be used any more. Instead the following formula should be used:

Ep = |(G*M*m)/r1 - (G*M*m)/r2|

Where

  • G is the gravitational constant, which is 6.674*10-11 N*m2/kg2
  • M is the mass of the planet in kg, in case of earth 5.972*1024kg
  • m is the mass of the object falling in kg
  • r2 is the distance between the center of mass of the planet and the center of mass of the object after the fall / before being lifted (in meters). So usually it is radius of the planet (in case of earth 6371000 m) + how far the object is away from the ground after the fall / before being lifted.
  • r1 is the distance between the center of mass of the planet and the center of mass of the object before the fall / after being lifted (in meters). So usually it is radius of the planet (in case of earth 6371000 m) + how far the object is away from the ground before the fall / after being lifted.
  • Ep is the gravitational potential energy difference in joules.

Terminal velocity

Air resistance is mostly relevant for the case of falling objects and even then can be ignored for most heavy objects like meteors or big constructs.
However for lightweight objects, like for example humans, it becomes relevant.
The air resistance opposes gravity in pulling the object down and due to that slows down the fall of the object, reducing the kinetic energy it gains while dropping.
If an object falls long enough it will reach its terminal velocity and not get any faster than that (provided it wasn't faster to begin with or influenced by other forces than gravity).
Because of that the kinetic energy an object has at terminal velocity often forms a limit to how much energy an object can gain through falling, which means that if our calculated change in potential energy is greater than that we have to consider it as a too high estimate for the energy when reaching the ground.
The terminal velocity of an object can be calculated like described here, but, for example due to the drag coefficient being depended on the fall speed of the object, it is in practice often difficult to calculate. For a human terminal velocity is approximately 53 m/s close to the ground.
An example of terminal velocity being relevant for the result of a calculation can be found here.

Change in Temperature and Vaporization or Melting Energy

This would be one way of determining attacks that make use of fire, ice, etc. If something is melted, ignited, or frozen we can determine destructive capacity for one or two steps:

First:

  • We determine the energy given or taken in changing the temperature, the equation for this is E=m*c*ΔT
  • E is the energy
  • m is mass
  • c is specific heat capacity, this varies between materials and is based on how much energy is required to get that material to a certain heat (if you put stone and steel over the same fire they will receive energy at the same rate but the steel will heat up faster)
  • ΔT is the change in temperature; the starting temperature will usually be a reasonable room temperature unless there is a reason why the temperature would begin hot or cold in the calculation, the final temperature will usually be either melting point, freezing point, boiling point, or (if a burnable material is present) the auto-ignition temperature or burning material; this is measured in kelvin.

Second:

  • We determine the energy given or taken in changing the state of matter (if the feat we are calculating did not involve a state change i.e. something being set on fire does not include a change of state, then we do simply perform this second step).
  • If the feat involved a change between solid and liquid (in either direction) we must multiply the mass of the material with the material's "heat of fusion".
  • If the feat involved a change between liquid and gas (in either direction) we must multiply the mass of the material with the material's "enthalpy of vaporization", this varies based on atmospheric pressure.

This type of feat will most often involve water:

Specific heat capacity of water is approximately 4181 J/kg°K (The precise value varies to some degree with temperature and pressure)

Heat of fusion for water is 334000 J/kg

Here a few pre-calculated example values (starting with the materials at 20°C):

  • Melting Granite: 4358.9475 J/cm^3
  • Melting Cement: 12232.65 J/cm^3
  • Melting Glass: 2494 J/cm^3
  • Freezing Water: 418 J/cm^3
  • Vaporization of water: 2575 J/cm^3
  • Vaporization of titanium: 49079.7 J/cm^3

(Values taken from here and here)

Specific Heat Capacity/Latent Heat of Fusion and Vaporization

Specific Heat Capacity Latent Heat (Fusion) Latent Heat (Vaporization) Melting Point Boiling Point
Silver 230 104726.6 5327260 962 1950
Iron 460 247112.54 6213627 1538 2861
Aluminum 870 396567.46 10859277 660.32 2519
Tin 240 58972 2442928 231.93 2602
Copper 390 206137 4720692 1084.62 2927
Zinc 380 112420 1820128 419.53 907
Silicon 710 1787113 12780350 1414 2900
Gold 130 63463 1675127 1064.18 2856
Calcium 630 213000 3867458 842 1484
Water 4186 334000 2264705.7 0 100
Granite 821.46 947657.98 6077872 1215 ?
Titanium 470 390666 8878768 1668 3287
Oxygen 919 13875 213125 -218.3 -182.9
Nitrogen 1040 25702 199190 -210.1 -195.8
  • Specific heat capacity = J/kg*K (K and °C are in this case interchangeable for most calculations)
  • Latent heat = J/kg
  • Boiling/Melting point = (°C)

Plasma

Plasma is one of the four fundamental states of matter, together with solid, liquid and gas.

A Plasma is an ionised gaseous substance, which is highly electrically conductive, to the point that long range electric and magnetic fields dominate the behavior of the matter.

The energy imbued into a plasma is highly variable. For example a candle flame is a form of plasma with very few energy and the matter that the core of the sun is made of is a plasma with very much energy.

As such the energy within a plasma or the energy necessary to create it can, in general, not be estimated without having further information.


Should the mass of the plasma, the material it is made of and the degree of ionization be known, one can estimate the energy as follows:

  1. Use the molar mass of the material the plasma is made of together with the mass to figure out the number of atoms in the plasma. So if you have 50 g of plasma, with your substance having a molar mass of 1.007 g/mol, then you have (50 g) / (1.007 g/mol) = 49.6524 mol of atoms = 6.022*1023 * 49.6524 atoms = 2.990067528*1025 atoms. Be careful: the molar mass of a non-atomic substance, like water, gives the amount of mass per molecules, not atoms.
  2. Next we want to calculate the amount of ionized atoms within the substance. If the degree of ionization of the substance is x, then this is simply done by multiplying x with the amount of atoms calculated in the first step.
  3. Now we can calculate the energy to turn it into plasma: For that we just have to multiply the amount of ionized atoms, with the Ionization energy of the atoms in question.

Consider that the energy that was used to turn the material into the state before it was made into a plasma is not considered here. So if for example rock is turned into plasma, the energy to vaporize it can be put on top of this calculation result.

If there are other specific statements those can possibly be used to get results in an easier way.

If a plasma is stated to operate under the rules of high energy density physics, it can be assumed to have an energy density of at least 1010 J/m3.

Heat, Radiation and Nuclear-like Explosions

When dealing with a feat that is heat related only, we can still manage to find Destructive capacity, by finding the given temperature of the object in question, estimate or calculate its surface area and emissivity, and apply the values to the following Calculator:

https://www.endmemo.com/physics/radenergy.php

While it does calculate joule/second, it is still reliable enough for us, though it should be noted that if the values inserted aren't extremely high, the results would likely be underwhelming. It is usually assumed that only 1 second of the calculated joules per second value contributes to the attack potency, or less if the object only had that heat for less than one second.

When dealing with an explosion that doesn't leave a crater behind, we can use the following Calculator:

https://www.stardestroyer.net/Empire/Science/Nuke.html

Although it is tricky to use, we need to find the radius of the explosion in question, and insert the megaton value into the calculator until we get the same value for the "Air Blast radius (near total fatalities)" as the radius that we have scaled.

Volume, Mass, Destruction Values and TNT table

Many feats cause visible destruction after they are preformed (such as leaving a crater, destroying a mountain/meteor). To measure these feats we need to know the Volume of the matter that was destroyed in the attack.

Volume is a space composed of three perpendicular dimensions, if its a mountain, it has length, width, and height. If it is a crater, it has length, width, and depth.

Here is a page with classic formulas of classic geometrical shapes that maybe useful when calculating volume:

https://www.basic-mathematics.com/volume-formulas.html

For example, sometimes, when trying to find the volume of a mountain, we may use the formula of a cone to give us a rough estimation of its size.

Usually after we have found the volume, we may get the final measurement to be in cubic meters (m^3) or sometimes in cubic kilometers (km^3). At this point, in order to get the Energy measurement for the feat, we need to convert the volume from whatever unit we are using, into cubic centimeters (cm^3 or cc).

Here are some terms that will make said conversion easier:

1 km^3 = 1000000000 m^3

1 m^3 = 1000000 cm^3

Destruction Values

According to the method used within the Naruto Forums, there are different methods of Destruction (for lack of a better term) that require different levels of energy for every cubic centimeter of the volume that was destroyed during the feat:

Fragmentation: Applied when the matter that was destroyed was turned into fairly large and distinguishable pieces. The value is 8 joules per Cubic centimeter (J/cc).

Violent Fragmentation: Applied when the matter that was destroyed was turned into small but still distinguishable pieces. The value is 69 (J/cc).

Pulverization: Applied when the matter that was destroyed was turned to dust. We usually use this value when we see no remains of the matter that was destroyed in the aftermath of the attack. The value is 214 (J/cc).

Melting: Applied when the matter that was destroyed was liquified. It should be important to note that some materials instead sublime (ex. carbon dioxide and graphite), kindle (ex. wood and rubber), or otherwise decompose (ex. sucrose). The value is 6174.5 (J/cc). Values used here are based on a starting temperature of 20°C.

Vaporization: Applied when the matter that was destroyed was vaporized during the attack. Much like for Pulverization, we usually use this value when we see no remains of the matter that was destroyed in the attack, but in addition there has to be a considerable amount of visible vapor and/or character statements that imply vaporization, usually the latter. The value is 25700 (J/cc).

Atomization: Applied only if clearly stated. It describes the energy to separate all atoms in a chemical substance. The value is 30852.2 (J/cc).

Subatomic Destruction: Applied only if clearly stated. It describes the energy necessary to destroy all atoms in a substance, by separating the particles in their nucleus. Note that Protons and Neutrons still stay intact. Value is 5.403E13 (J/cc).

These values are only relevant for solid objects like rocks, buildings and mountains.

After we have determined both the method of destruction and the volume (in cubic centimeters), we multiply both Values to get the value of energy that was exerted for the feat, and thus we have the destructive capacity.

Table of Destruction Values

Fragmentation Violent Fragmentation Pulverization Melting Vaporization Atomization Subatomic Destruction
Rock (General) 8 J/cc 69 J/cc 214 J/cc 6174.5 J/cc 25700 J/cc 30852.2 J/cc 5.403E13 J/cc
Iron 20 J/cc 42.43 J/cc 90 J/cc 7312.54 J/cc 60915.7 J/cc 58401 J/cc 6.6965E12 J/cc
Steel 208 J/cc 568.5 J/cc 310-1000 J/cc 6916.07-7778.62 J/cc 59526.65 J/cc 6.7034E12 J/cc
Stainless Steel 358 J/cc 597 J/cc 1631 J/cc 7208.52-7703.06 J/cc
Grey Cast iron 400 J/cc 613.5 J/cc 827 J/cc
Damascus Steel 814.5 J/cc
Wrought Iron 194.22 J/cc 308.76 J/cc 699 J/cc
Silver 65 J/cc 204 J/cc 300 J/cc 3420.53 J/cc 31177.58 J/cc 27669.25 J/cc 8.983E12 J/cc
Aluminum/Aluminium 48.75 J/cc 234 J/cc 280 J/cc 2633.63 J/cc 35190.2 J/cc 32241.5 J/cc 2.172E12 J/cc
Tin 5.5 J/cc 10.8 J/cc 11 J/cc 767.23 J/cc 22317.22 J/cc 18693.24 J/cc 6.058E12 J/cc
Copper 172.37 J/cc 217.1 J/cc 330 J/cc 5514.58 J/cc 52455.62 J/cc 47784.97 J/cc 7.11E12 J/cc
Bronze 297 J/cc 538 J/cc 641 J/cc 3894.61-5215.66 J/cc
Brass 205 J/cc 531 J/cc 489.528-689.476 J/cc 4124.23-4458.59 J/cc
Zinc 45 J/cc 120 J/cc 160 J/cc 1909.5 J/cc 15402.32 J/cc 13758.07 J/cc 5.982E12 J/cc
Silicon 56.5 J/cc 67.8 J/cc 120 J/cc 6470.81 J/cc 34542.6 J/cc 36484.37 J/cc 1.895E12 J/cc
Carbon 11.7 J/cc 22-33 J/cc 51 J/cc N/A (sublimes) 141159.06 J/cc 156545 J/cc 1.9414E12 J/cc
Diamond 110000 J/cc N/A (sublimes) 215767.74 J/cc 210081 J/cc
Tungsten 400 J/cc 1412.5 J/cc 2425 J/cc 12309.35 J/cc 88098.07 J/cc
Gold 50 J/cc 132 J/cc 205 J/cc 3826.54 J/cc 39486.35 J/cc 36058.28 J/cc 1.474E13 J/cc
Calcium 8.22-24 J/cc 27-66 J/cc 12-60 J/cc 1134.24 J/cc 7116.124 J/cc 1.276E12 J/cc
Titanium 550 J/cc 760 J/cc 970 J/cc 5623.05 J/cc 49097.7 J/cc
Sulfur 0.197 J/cc 2.568 J/cc 12.41-22.75 J/cc 237.33 J/cc 1291.77 J/cc
Chromium 166.67 J/cc 194.44 J/cc 360.32-417.46 J/cc 8912.99 J/cc 58250.71 J/cc
Water N/A (Liquid) N/A (Liquid) N/A (Liquid) N/A (Liquid) 2575 J/cc 51384.16 J/cc 8.9363E12 J/cc
Ice 0.5271 J/cc 0.825 J/cc 4.3919 J/cc See Table Below 51384.16 J/cc 8.9363E12 J/cc
Human Body 4.4 J/cc 7.533 J/cc 12.9 J/cc 4638.75 J/cc 72416.33 J/cc 1.09729000691E10 J/cc
Bone 51.6 J/cc 67.5 J/cc 170 J/cc 4763.49-5145.83 J/cc
Granite 14 J/cc 103.42-175 J/cc 203.25 J/cc 3142.935-3319.92 J/cc 27050 J/cc
Concrete 2-6 J/cc 17-20 J/cc 40 J/cc 4814.5 J/cc 5304 J/cc 4.168E12 J/cc
Reinforced Concrete 10 J/cc 61.2 J/cc 610 J/cc
Cement 6 J/cc 17-20 J/cc 40 J/cc 4814.5 J/cc 5304 J/cc 4.168E12 J/cc
Red/Mud/Clay Brick 0.51 J/cc 2.81-5.65 J/cc 19.28-24.37 J/cc 2052.975-3022.9 J/cc
Soil 0.15 J/cc 0.2 J/cc 0.4-1 J/cc
Sand 96.3 mJ/cc 0.17236 J/cc 1-1.2 J/cc 2041.37 J/cc
Marble 9 J/cc 62.1-103.42 J/cc 154.95 J/cc 1684.74-3166.83 J/cc
Limestone 10 J/cc 50-140 J/cc 250 J/cc
Sandstone 8 J/cc 55.16-95 J/cc 144.7 J/cc
Slate 15 J/cc 103.42-150 J/cc 172.5 J/cc
Basalt 20 J/cc 60-200 J/cc 224 J/cc 2123.61-3716.12 J/cc
Ceramic 3.4 J/cc 4.53 J/cc 2393.33 J/cc
Silica/Quartz (Crystal Generalization) 28.8 J/cc 70-93 J/cc 1100 J/cc 3748.65 J/cc
Glass 1000 J/cc 935.83-2919.84 J/cc (type-dependent)
Ballistic glass 32.41 J/cc 38.89 J/cc

Values taken from here, here, here, here, here, here, here, here, here, here, and here.

Red brick destruction values taken from here (Fragmentation), here (Violent fragmentation), here and here (Pulverization).

We are aware that these values don't capture the complex topic of destruction of materials in real life, which involve many factors like toughness, surface area, force (pressure), area of effect, etc. However, since they are widely established, and fit our simplified attack potency system better (as it is based on an easier to follow linear energy system), it is not possible to switch to a more accurate system at this point, as we concluded in a discussion here.

We have also tried using the more-accurate Kuz-Ram model used in rock-blasting which would serve our purposes for accurately calculating the destruction of rock, and acknowledge that pulverization strength in real life calculated via the Kuz-Ram model is much higher than compressive strength which we currently use for our pulverization feats. This is due to other factors like compressive strength being a slow process unlike true pulverization (reducing to dust particles), and that compressive strength does not account for impact loading or impact strikes (rapid punching) which is common in fiction. However, eventually it was discovered it could only be used for normal fragmentation and pulverization, that it varied wildly depending upon rock type, and even then it could not be used for non-rock materials like metal, wood and the like, making it unfeasible to apply as a standard method for calculation values, as discussed in this thread.

Melting Values for Ice

Ice's melting depends on the temperature at which it is melted from. Below is a table for the melting values of ice at commonly-used temperatures.


Temperature

Density of Ice

Melting Value
Near 0°C (-0.15°C used) 0.9167 g/cm³ 306.0529 J/cc
-5°C 0.91765 g/cm³ 315.6114 J/cc
-10°C 0.9183 g/cm³ 324.9405 J/cc
-20°C 0.9196 g/cm³ 342.78 J/cc

Destruction values of wood

Below are detailed tables of destruction values of wood. In most cases, it should be fine to assume that the wood destroyed is white oak, which has a fragmentation value of 7.3774 J/cc, a violent fragmentation value of 13.7895 J/cc and a pulverization value of 51.297 J/cc. Wood starts kindling at 107.1031 J/cc.

Table of Destruction Values - Hard Wood

Fragmentation

Violent Fragmentation

Pulverization
Ash, White 7.9979 J/cc 13.1690 J/cc 48.8149 J/cc
Ash, Black 5.2400 J/cc 10.8248 J/cc 41.1617 J/cc
Birch, Paper 4.1369 J/cc 8.3427 J/cc 39.2312 J/cc
Cherry, Black 4.7574 J/cc 11.72108739 J/cc 49.02172433 J/cc
Cottonwood, Balsam Poplar 2.0684 J/cc 5.4469 J/cc 27.7169 J/cc
Elm, Rock 8.4806 J/cc 13.2379 J/cc 48.6080 J/cc
Maple, Black 7.0327 J/cc 12.5485 J/cc 46.0570 J/cc
Maple, Red 6.8948 J/cc 12.7553 J/cc 45.0917 J/cc
Maple, Sugar 10.1353 J/cc 16.0648 J/cc 53.9859 J/cc
Oak, Black 6.4121 J/cc 13.1690 J/cc 44.9538 J/cc
Oak, Chestnut 5.7916 J/cc 10.2732 J/cc 47.0912 J/cc
Oak, Live 18.3401 J/cc 19.5811 J/cc 61.3633 J/cc
Oak, Post 9.8595 J/cc 12.6864 J/cc 45.5054 J/cc
Oak, Northern Red 6.9637 J/cc 12.2727 J/cc 46.6086 J/cc
Oak, White 7.3774 J/cc 13.7895 J/cc 51.2970 J/cc
Sycamore, American 4.8263 J/cc 10.1353 J/cc 37.0938 J/cc
Walnut, Black 6.9637 J/cc 9.4458 J/cc 52.2623 J/cc
Willow, Black 2.9647 J/cc 8.6184 J/cc 28.2685 J/cc
Yellow Poplar 3.4474 J/cc 8.2048 J/cc 38.1970 J/cc
Table of Destruction Values - Soft Wood

Fragmentation

Violent Fragmentation

Pulverization
Cedar, Northern White 2.1374 J/cc 5.8605 J/cc 27.3032 J/cc
Douglas-fir, Coast 5.5158 J/cc 7.7911 J/cc 49.8491 J/cc
Fir, White 3.6542 J/cc 7.5842 J/cc 39.9896 J/cc
Hemlock, Mountain 5.9295 J/cc 10.6179 J/cc 44.4022 J/cc
Pine, Eastern white 3.0337 J/cc 6.2053 J/cc 33.0948 J/cc
Pine, Red 4.1369 J/cc 8.3427 J/cc 41.8512 J/cc
Redwood, Young-growth 3.5853 J/cc 7.6532 J/cc 35.9906 J/cc
Spruce, White 2.9647 J/cc 6.6879 J/cc 35.7148 J/cc

TNT Measurements

Most of the time, when calculating Destructive capacity, we end up with extremely large values of energy that are very long to write, also, even if using Orders of magnitude to "shorten" the number, for most people, these large values of energy mean nothing and they cannot rank them easily. That is why we need to convert the numbers we get to TNT measurements, as it is a measuring system that is easier to understand for a wider diversity of people. For even higher energy values we use Foes.

To understand the TNT measuring system, we must first explain how it works: 1 gram of TNT contains about 4184 joules of energy. Therefore we can say that every 4184 joules equals 1 gram of TNT, and from here we establish a measuring system:

In common units In prior unit In tons of TNT
In Joule
1 gram of TNT
- 10^-6 tons of TNT 4184 J
1 kg of TNT 1000 gram of TNT 10^-3 tons of TNT 4184000 J
1 ton of TNT 1000 kg of TNT 1 ton of TNT 4.184*10^9 J
1 Kiloton of TNT 1000 tons of TNT 1000 tons of TNT 4.184*10^12 J
1 Megaton of TNT 1000 Kilotons of TNT 10^6 tons of TNT
4.184*10^15 J
1 Gigaton of TNT 1000 Megatons of TNT 10^9 tons of TNT 4.184*10^18 J
1 Teraton of TNT 1000 Gigatons of TNT 10^12 tons of TNT 4.184*10^21 J
1 Petaton of TNT 1000 Teratons of TNT 10^15 tons of TNT 4.184*10^24 J
1 Exaton of TNT 1000 Petatons of TNT 10^18 tons of TNT 4.184*10^27 J
1 Zettaton of TNT 1000 Exatons of TNT 10^21 tons of TNT 4.184*10^30 J
1 Yottaton of TNT 1000 Zettatons of TNT 10^24 tons of TNT 4.184*10^33 J
1 Ronnaton of TNT 1000 Yottatons of TNT 10^27 tons of TNT 4.184*10^36 J
1 Quettaton of TNT 1000 Ronnatons of TNT 10^30 tons of TNT 4.184*10^39 J
1 Foe 23900 Quettatons of TNT 2.39*10^34 tons of TNT 10^44 J
1 KiloFoe 1000 Foe 2.39*10^37 tons of TNT 10^47 J
1 MegaFoe 1000 KiloFoe 2.39*10^40 tons of TNT 10^50 J
1 GigaFoe 1000 MegaFoe 2.39*10^43 tons of TNT 10^53 J
1 TeraFoe 1000 GigaFoe 2.39*10^46 tons of TNT 10^56 J
1 PetaFoe 1000 TeraFoe 2.39*10^49 tons of TNT 10^59 J
1 ExaFoe 1000 PetaFoe 2.39*10^52 tons of TNT 10^62 J
1 ZettaFoe 1000 ExaFoe 2.39*10^55 tons of TNT 10^65 J
1 YottaFoe 1000 ZettaFoe 2.39*10^58 tons of TNT 10^68 J
1 RonnaFoe 1000 YottaFoe 2.39*10^61 tons of TNT 10^71 J
1 QuettaFoe 1000 RonnaFoe 2.39*10^64 tons of TNT 10^74 J
1 QuettaexaFoe 10^18 QuettaFoe
2.39*10^82 tons of TNT 10^92 J

Now, to convert the Energy value to a TNT measurement, we need to divide the energy value by 4.184, and then divide the result of that division by the highest order of magnitude (that is divisible by 3) that is lower/equal to the order of magnitude that was received after the first division, and that will tell you the TNT measurement. For example:

Where does 2*10^24 (j) register on the TNT Measurement system?

(2*10^24) / 4.184 = 4.78*10^23

(4.78*10^23) / 10^21= 478

This was divided by 10^21 because it was the highest order of magnitude that was both divisible by 3 and lower than the order of magnitude of the number that was received after dividing by 4.184, and since the value was divided by 10^21, the TNT measurement is in teratons, according to the chart above:

2 * 10^24 (j) = 478 Teratons.

Mass

When you need to determine the mass of an object, you must first find its volume. Then you must estimate from what type of substance that the object is made out of, as every substance has its own density:

Mass = Volume * Density.

Here is a chart of densities of common materials:

  • Continental crust, stone and earth: 2700 kg/m^3
  • Meteors: 3000-3700 kg/m^3
  • Concrete: 2400 kg/m^3
  • Water: 1000 kg/m^3

For things like buildings and vehicles the fact that they are hollow has to be considered. The specific values vary based on the building or vehicle in question, although often 80% to 90% hollowness is assumed. For things like skyscrapers one could orientate onself on the approximately 87.05% hollowness of the Empire State Building.

Speed Calculations

To calculate the speed of a character or object the basic formula used is v = d/t, where v is the speed of the object, d is the distance the object moved and t is the amount of time it took the character/object to move that much.
Usually the time it took for an object to move the distance is calculate by dividing the distance another object moved during that time, through the speed of that object. That requires knowing the speed of the other object, of course.

More details, such as more in depth explanations on how to figure out the distance and the time as well as examples on how to calculate speed, can be found on the following pages:

Slow Motion Calculations

Sometimes when calculating speed one might encounter scenes where time seems to move slowly from the perspective of a fast moving character. Fundamentally speed calculations can be performed in the same way as normal in such cases.

In other words one just has to figure out a timeframe through the movement of a reference object with known speed, measure how far the character moved during that timeframe and divide the distance through the length of the timeframe (v = d/t).

However, sometimes the time is not just slowed down, but appears outright frozen.

In this case, if a reference object with known speed can be visually confirmed to not have moved even 1 pixel (which requires the feat to happen in a visual media like a comic, movie or animation) one can figure out the timeframe, by saying that it must have been less than the timeframe that the object would have taken to move 1 pixel.

If that can not be confirmed different upper limits, with similar argumentation, can usually be confirmed. In cases with a moving camera/point of view it can be useful to compare the movement to an object that can be assumed to be static.


Especially for written feats another method can be relevant. In that one first wants to figure out how many times slower the time is from the real time and then figure out how fast a movement in that time really is, based on how fast it looks in the slowed down time.

So the formula would be (real speed of reference object / apparent speed of reference object) * apparent speed of object of interest = real speed of object of interest

For example: If an object that really is 1000 m/s fast seems to move with only 10 m/s in slowed down time a character that seems to move with a human walking speed of 1.4 m/s in slowed time would move with (1000 m/s / 10 m/s) * 1.4 m/s = 140 m/s.

Useful values for the apparent speed of movement would be:

Sometimes even something like "time seems frozen" or that nothing moves is stated. Often these kinds of statements are hyperbole. However, should that not be the case one may assume that the apparent speed of the reference object is less than or equal to 0.00275 m/s, as that's the top speed of garden snails, animals that move so slowly that they appear to be nearly frozen in our perspective. Various sources have measured the speed of snails at around 0.0024 m/s, and even going as slow as 0.001625 m/s.

Mind rule 7 regarding Cinematic Time, whenever calculating feats involving slowed time.

Do not assume that a character viewing the world in slow motion is caused by time dilation. The depiction usually doesn't match the real life phenomena and the effect is commonly caused by the character being able to process events very fast, so that they seem to happen in slow motion to them, instead.

Moving faster than the eye can see

Human vision is a complex topic, as the eye doesn't quite work like a camera and the brain processes the image given by the eye a lot to produce the image we see. Hence common figures like the "framerate" of the human eye can't simply be used to evaluate feats of moving faster than the eye can see.

Since we can clearly see human sized moving objects such as motorcyclists or skydivers it can be assumed that characters which move faster than the human eye can see should move faster than those, granting them at least Subsonic speed. That should only be assumed under regular seeing conditions. However, if the person whose point of view we take has bad eyesight, if the target is camouflaged or very far away, or if the surroundings are extraordinarily bright or dark the feat can possibly not be used as normal conditions of vision aren't given.

Throwing Feats

For feats of throwing or launching a projectile, the formulas and calculators found on this page can be used, provided the projectile is not launched more than dozens of kilometers high or so far that the curvature of the planet becomes relevant.

A particularly useful formula is v = sqrt( R * g / ( sin(2 * a) ) ), where v is the initial launching / throwing speed, R is the distance the object is thrown, g is the gravitational acceleration (9.81 m/s^2) and a is angle between the ground and the direction the projectile gets launched in. Ensure that the angle is given in the same unit used for the sinus (i.e. either both degrees or both radians). A useful approximation is to use a = 45° as that will result in a low-end estimate for the projectile's speed and hence doesn't require actual measurement of the angle.

Note that throwing speed is typically not applied to combat speed, but only treated as attack speed, as it is usually considered a feat of strength more so than a measure of how fast the character can run or fight.

Evading Punches

Refrain from calculating feats based on dodging attacks from other characters at extreme proximity, as this is primarily a trope used to exaggerate a narrow miss rather than a literal representation of overwhelming speed. Taking it at face value is often inconsistent with the battle in which the feat occurs, where the opponents are presented as equals, but the calculation results in them being considered several times faster. This should only be used when the character in question is greatly superior to the one who's attack he is evading and the speed of the attack is concretely stated, such as being able to surpass the speed of sound, or light, or uses a basis in the Real World such as the speed of an athlete's punch. If the two fighters are equal, you should simply scale them to the stated speed of the attack, or off of other feats they perform.

Linear Motion Equations

Linear motion, often referred to as "rectilinear motion," is a one-dimensional motion along a straight line, and can be described mathematically using one spatial dimension. It's a fundamental concept in physics that many of us might have encountered during our high school years.

The primary equations governing linear motion are:

  1. V = U + a × t
  2. V2 = U2 + 2 × a × S
  3. S = U × t + 0.5 × a × t2
  4. S = 2 (V + U) ​× t

Where:

  • "V" represents the final velocity.
  • "U" represents the initial velocity. It's typically 0 if the object began moving from rest, but if you have the initial speed, you can use it.
  • "a" stands for the constant acceleration. This can also represent gravity if the object is falling straight down.
  • "t" represents the time the object moves.
  • "S" represents the distance covered.

These equations are versatile and can be applied to various scenarios. If you have at least three out of the four variables, you can select an equation that accommodates those variables and includes the one you're looking to find. Then, you can solve for that variable for any straight line motion.

Note that when considering the case of gravity, especially in scenarios where objects are falling towards the Earth, it's essential to acknowledge the complexities introduced by air resistance. Air resistance can significantly affect the motion of an object, especially if it's lightweight or has a large surface area. Moreover, the equations provided primarily hold true for motions close to the ground. As the altitude increases, factors like decreasing air density and gravitational variations can further complicate the calculations.

Calculators and other utilities

Calculators

Other utilities

Planck

Planck units, they come up often enough in VS debating

See also:

Discussions

Discussion threads involving Calculations
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